 
Y′′ + 4y = cos2x+ sin2xtg2x
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вотттт или как. Ттроьтттьаьалвбьалсьсьмтатаьвьлцдцбвб.сбсба


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            To solve the differential equation , we'll start by simplifying the right-hand side expression :
(because is the fundamental trigonometric identity)
So, we have:
Now, the differential equation becomes:
This is a second-order linear homogeneous differential equation with a non-homogeneous term. To solve it, we'll first solve the homogeneous part , and then we'll find a particular solution for the non-homogeneous term . Finally, we'll combine the solutions.
Homogeneous Part:
The characteristic equation for the homogeneous part is . Solving for :
So, the characteristic roots are complex (imaginary). Therefore, the general solution to the homogeneous part is:
Particular Solution:
To find a particular solution for the non-homogeneous term , we'll use the method of undetermined coefficients. We assume a particular solution of the form:
Now, we'll find the derivatives needed for the equation:
Now, we can plug these derivatives into the original differential equation:
Now, we equate this to the right-hand side of the original equation, which is :
Simplifying:
Now, we can equate coefficients:
So, the particular solution is:
General Solution:
Now, we can combine the general solution to the homogeneous part and the particular solution:
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