Question

3х2-7+4=0; 5х2-8х+3=0; 3х2-13х+14=0; 2у2-9у+10=0

Answer 1

Данный ответ представлен фотографиями.

Answer 2

It seems like you've provided a set of quadratic equations. To solve these equations for x and y, we can use the quadratic formula:

For a quadratic equation of the form ax^2 + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b² - 4ac)) / (2a)

Let's solve each of the equations one by one:

1. 3x^2 - 7x + 4 = 0: a = 3, b = -7, c = 4 Using the quadratic formula: x = (7 ± √((-7)² - 4 * 3 * 4)) / (2 * 3) x = (7 ± √(49 - 48)) / 6 x = (7 ± √1) / 6

   So, the solutions are: x1 = (7 + 1) / 6 = 8/6 = 4/3 x2 = (7 - 1) / 6 = 6/6 = 1

2. 5x^2 - 8x + 3 = 0: a = 5, b = -8, c = 3 Using the quadratic formula: x = (8 ± √((-8)² - 4 * 5 * 3)) / (2 * 5) x = (8 ± √(64 - 60)) / 10 x = (8 ± √4) / 10

   So, the solutions are: x1 = (8 + 2) / 10 = 10/10 = 1 x2 = (8 - 2) / 10 = 6/10 = 3/5

3. 3x^2 - 13x + 14 = 0: a = 3, b = -13, c = 14 Using the quadratic formula: x = (13 ± √((-13)² - 4 * 3 * 14)) / (2 * 3) x = (13 ± √(169 - 168)) / 6 x = (13 ± √1) / 6

   So, the solutions are: x1 = (13 + 1) / 6 = 14/6 = 7/3 x2 = (13 - 1) / 6 = 12/6 = 2

4. 2y^2 - 9y + 10 = 0: This is a quadratic equation in terms of y. You can solve it in a similar manner as the x equations using the quadratic formula. In this case, a = 2, b = -9, and c = 10. Calculate the solutions for y using the quadratic formula in the same way as above.

Note that these solutions represent the values of x and y that satisfy each equation.