Question

X-12x(1-3x)=14-(5-6x)(6x+5)​

Answer 1

Объяснение:

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Answer 2

To solve the equation $12x(1-3x) = 14 - (5-6x)(6x+5)$, you'll need to simplify and solve for $x$. Here are the steps to do that:

1. Expand the expressions on both sides of the equation:

   $12x(1-3x) = 14 - (5-6x)(6x+5)$

   $12x - 36x^2 = 14 - (30x^2 + 25x - 6x^2 - 5)$

2. Distribute the negative sign on the right side of the equation:

   $12x - 36x^2 = 14 - 30x^2 - 25x + 6x^2 + 5$

3. Now, combine like terms on both sides of the equation:

   $12x - 36x^2 = -30x^2 - 25x + 6x^2 + 19$

4. Move all terms to one side of the equation to set it to zero:

   $12x - 36x^2 + 30x^2 + 25x - 19 = 0$

5. Combine the $x^2$ terms and $x$ terms:

   $-6x^2 + 37x - 19 = 0$

6. This is a quadratic equation. To solve for $x$, you can use the quadratic formula:

   $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

   In this case, $a = -6$, $b = 37$, and $c = -19$.

   $x = \frac{-37 \pm \sqrt{37^2 - 4(-6)(-19)}}{2(-6)}$

   $x = \frac{-37 \pm \sqrt{1369 - 456}}{-12}$

   $x = \frac{-37 \pm \sqrt{913}}{-12}$

So, the solutions for $x$ are:

$x_1 = \frac{-37 + \sqrt{913}}{-12}$ and $x_2 = \frac{-37 - \sqrt{913}}{-12}$