Question

3х + 2y = 8, у – 2x = -3 и х— 2y = 0, 3у-*х=-1 * =

Answer 1

Ответ:

3х-2у=1

x-2y=0

qweyeyeywywyeyyeryr

Answer 2

To solve this system of equations, you can use the method of substitution or elimination. Let's use the elimination method to find the values of x and y.

The system of equations is:

1. 3x + 2y = 8
2. y - 2x = -3
3. x - 2y = 0
4. 3y - x = -1

We can start by eliminating one variable from each pair of equations:

From equations (2) and (3), let's eliminate x:

2. y - 2x = -3
3. x - 2y = 0

To eliminate x, multiply equation (2) by 3 and equation (3) by 2 so that the coefficients of x will cancel each other:

6. 3(y - 2x) = 3(-3)
7. 2(x - 2y) = 2(0)

This simplifies to:

6. 3y - 6x = -9
7. 2x - 4y = 0

Now, let's add equations (6) and (7) to eliminate x:

(3y - 6x) + (2x - 4y) = (-9) + 0

This simplifies to:

3y - 6x + 2x - 4y = -9

Combine like terms:

(3y - 4y) + (-6x + 2x) = -9

-y - 4x = -9

Now, let's isolate y:

-y = -9 + 4x

Multiply both sides by -1 to solve for y:

y = 9 - 4x

Now that we have the value of y, we can substitute it into one of the original equations to find the value of x. Let's use equation (1):

1. 3x + 2y = 8

Substitute the expression for y:

3x + 2(9 - 4x) = 8

Now, solve for x:

3x + 18 - 8x = 8

Combine like terms:

-5x + 18 = 8

Subtract 18 from both sides:

-5x = 8 - 18 -5x = -10

Now, divide by -5 to find the value of x:

x = -10 / -5 x = 2

So, the solution to the system of equations is:

x = 2 y = 9 - 4x y = 9 - 4(2) y = 9 - 8 y = 1

The values of x and y are:

x = 2 y = 1