Question

(x+7)(x-2)-(x+4)(x+3)=-2

Answer 1

Х=-12.................

Answer 2

To solve the equation $(x+7)(x-2)-(x+4)(x+3)=-2$, you can follow these steps:

1. Expand both sides of the equation: $(x+7)(x-2)-(x+4)(x+3)=-2$ $(x^2 - 2x + 7x - 14) - (x^2 + 3x + 4x + 12) = -2$

2. Simplify the equation by combining like terms within each parenthesis: $(x^2 + 5x - 14) - (x^2 + 7x + 12) = -2$

3. Distribute the negative sign into the second parenthesis: $(x^2 + 5x - 14) - x^2 - 7x - 12 = -2$

4. Combine like terms on both sides of the equation: $(x^2 - x^2) + (5x - 7x) + (-14 - 12) = -2$ $-2x - 26 = -2$

5. Add 26 to both sides of the equation to isolate the term with 'x': $-2x - 26 + 26 = -2 + 26$ $-2x = 24$

6. Finally, divide both sides by -2 to solve for 'x': $-2x / -2 = 24 / -2$ $x = -12$

So, the solution to the equation is $x = -12$.