Question

2m(m-n)-n+m 4q(p-1)+1-p

Answer 1

2m(m-n)-n+m = (m-n)(2m+1)

4q(p-1)+1-p=4q*(p-1)-1*(p-1)=(p-1)*(4q-1)

Answer 2

It looks like you have two expressions. Let's simplify each of them:

1. 2m(m-n) - n + m:

   To simplify this expression, you can start by distributing the 2m on the terms inside the parentheses:

   2m(m) - 2m(n) - n + m

   Now, let's combine like terms:

   2m^2 - 2mn - n + m

2. 4q(p-1) + 1 - p:

   Similar to the previous expression, distribute the 4q inside the parentheses:

   4q(p) - 4q(1) + 1 - p

   Now, combine like terms:

   4pq - 4q + 1 - p

So, the simplified forms of the two expressions are:

1. 2m^2 - 2mn - n + m

2. 4pq - 4q + 1 - p