Question

1). ( 2х – у ) (2х + у ) = 2). (2х – 1 )2 = 3). (а + 3 )2 = 4). ( а + 2х ) 3= 5). ( р – 3q ) 3= 6). ( у + 3 ) 3 =​

Answer 1

Ответ:

$(2x-y)(2x+y)=4x^2-y^2$

$(2x-1)2=2*2x-2*1=4x-2$

$(a+3)2=a*2+3*2=2a+6$

$(a+2x)3=a*3+2x*3=3a+6x$

$(p-3q)3=p*3-3q*3=3p-9q$

$(y+3)3=y*3+3*3=3y+9$

Answer 2

Sure, I can help you expand these expressions. Here are the expanded forms of the given expressions:

1. (2x - y)(2x + y) = 4x^2 - y^2

2. (2x - 1)^2 = 4x^2 - 4x + 1

3. (a + 3)^2 = a^2 + 6a + 9

4. (a + 2x)^3 = a^3 + 6a^2x + 12ax^2 + 8x^3

5. (p - 3q)^3 = p^3 - 9p^2q + 27pq^2 - 27q^3

6. (y + 3)^3 = y^3 + 9y^2 + 27y + 27