Question

1) (4x+5)²-(4x+3)²=0​

Answer 1

Ответ:

(4x+5)²-(4x+3)²=0

(4х+5-4х+3)(4х+5+4х+3)

2(8х+8)

2•8(х+1)

16(х+1)

Answer 2

To solve the equation (4x + 5)² - (4x + 3)² = 0, you can use the difference of squares formula:

a² - b² = (a + b)(a - b)

In this case, let a = (4x + 5) and b = (4x + 3). Now, apply the difference of squares formula:

(4x + 5)² - (4x + 3)² = [(4x + 5) + (4x + 3)][(4x + 5) - (4x + 3)]

Now, simplify each factor:

(4x + 5) + (4x + 3) = 8x + 8 (4x + 5) - (4x + 3) = 2

So, the equation becomes:

(8x + 8)(2) = 0

Now, you can solve for x:

8x + 8 = 0

Subtract 8 from both sides:

8x = -8

Divide by 8:

x = -1

So, the solution to the equation is x = -1.