Question

9а²-24ав+16в²- 25_______________=? 3а-4в-5. а=1/9 в=2 2/3​

Answer 1

Ответ:

Решение представлено на фотографии

Answer 2

Ответ:

0

Объяснение:

1) (3а-4б)²-25/3а-4б-5= 3а-4б+5

при а=1/9 б=2 2/3

3*1/3-4*2 2/3 + 5=0

Answer 3

To simplify the expression $9a^2 - 24ab + 16b^2 - 25$ when $a = \frac{1}{9}$ and $b = \frac{2}{3}$, we can substitute these values into the expression and then simplify:

$9\left(\frac{1}{9}\right)^2 - 24\left(\frac{1}{9}\right)\left(\frac{2}{3}\right) + 16\left(\frac{2}{3}\right)^2 - 25$

Now, let's calculate each term step by step:

1. $9\left(\frac{1}{9}\right)^2 = 9\left(\frac{1}{81}\right) = \frac{9}{81} = \frac{1}{9}$
2. $24\left(\frac{1}{9}\right)\left(\frac{2}{3}\right) = 24\left(\frac{2}{27}\right) = \frac{48}{27} = \frac{16}{9}$
3. $16\left(\frac{2}{3}\right)^2 = 16\left(\frac{4}{9}\right) = \frac{64}{9}$

Now, substitute these values back into the expression:

$\frac{1}{9} - \frac{16}{9} + \frac{64}{9} - 25$

Next, add and subtract the fractions:

$\left(\frac{1}{9} + \frac{64}{9}\right) - \frac{16}{9} - 25$

$\frac{65}{9} - \frac{16}{9} - 25$

Now, subtract the fractions:

$\frac{65 - 16}{9} - 25$

$\frac{49}{9} - 25$

Now, subtract 25 from $\frac{49}{9}$:

$\frac{49}{9} - \frac{225}{9} = \frac{49 - 225}{9} = \frac{-176}{9}$

So, the simplified expression is $\frac{-176}{9}$ when $a = \frac{1}{9}$ and $b = \frac{2}{3}$.