Question

(x-4) (x+2) ;2) (4a-b) (2a+3b) ;3) (y-5) (y2-2y+3)

Answer 1

Ответ:

1)x²+2x-4x-8=x²-2x-8

2)8a²+12ab-2ab-3b²=8a²+10ab-3b²

3)y³-2y²+3y-5y²+10y-15=y³-7y²+13y-15

Объяснение:

Answer 2

It looks like you're asked to multiply various binomial expressions. Let's go ahead and perform each multiplication step by step:

1. $(x-4) (x+2)$ Expand using the FOIL method:

   $$\begin{align*} (x-4)(x+2) &= x(x) + x(2) - 4(x) - 4(2) \\ &= x^2 + 2x - 4x - 8 \\ &= x^2 - 2x - 8. \end{align*}$$

2. $(4a-b)(2a+3b)$ Again, use the FOIL method:

   $$\begin{align*} (4a-b)(2a+3b) &= 4a(2a) + 4a(3b) - b(2a) - b(3b) \\ &= 8a^2 + 12ab - 2ab - 3b^2 \\ &= 8a^2 + 10ab - 3b^2. \end{align*}$$

3. $(y-5)(y^2-2y+3)$ Once more, apply the FOIL method:

   $$\begin{align*} (y-5)(y^2-2y+3) &= y(y^2) + y(-2y) + 5(y^2) + 5(-2y) + 5(3) \\ &= y^3 - 2y^2 + 5y^2 - 10y + 15 \\ &= y^3 + 3y^2 - 10y + 15. \end{align*}$$