Question

A)3-5x=0.3(2x+1) b)1-3(x-5)=7(3-2x)

Answer 1

Ответ:

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Answer 2

Let's solve these two equations step by step:

A) 3 - 5x = 0.3(2x + 1)

First, distribute the 0.3 on the right side of the equation:

3 - 5x = 0.6x + 0.3

Now, let's isolate x on one side of the equation. First, subtract 0.6x from both sides:

3 - 5x - 0.6x = 0.3

Combine like terms:

3 - 5.6x = 0.3

Next, subtract 3 from both sides to isolate the variable:

-5.6x = 0.3 - 3

-5.6x = -2.7

Now, divide both sides by -5.6 to solve for x:

x = -2.7 / -5.6 x ≈ 0.4821

So, the solution to equation A) is approximately x ≈ 0.4821.

B) 1 - 3(x - 5) = 7(3 - 2x)

First, distribute the constants on both sides of the equation:

1 - 3x + 15 = 21 - 14x

Combine like terms:

16 - 3x = 21 - 14x

Now, let's isolate x on one side of the equation. First, add 14x to both sides:

16 - 3x + 14x = 21

Combine like terms:

16 + 11x = 21

Next, subtract 16 from both sides to isolate the variable:

11x = 21 - 16

11x = 5

Now, divide both sides by 11 to solve for x:

x = 5 / 11

So, the solution to equation B) is x = 5/11.