Question

2х+3у= 5аб-10а²=6а²х³-4а³х²+2а²х²=5х*(х-6)=0(уравнение)2х²+18х=0(уравнение)9*(х+4)+х+4=2х²-3х+6а-4ах=​

Answer 1

Ответ:

Вот ❤️ половину сделала

Объяснение:

1) 5xy

2) 5a•(b-2a)

3) 2a² x² •(3x-2a+1)

Answer 2

It looks like you've provided a set of equations. Let's go through them one by one:

1. $2x + 3y = 5ab - 10a^2$
2. $5ab - 10a^2 = 6a^2x^3 - 4a^3x^2 + 2a^2x^2$
3. $5x(x - 6) = 0$
4. $2x^2 + 18x = 0$
5. $9(x + 4) + x + 4 = 2x^2 - 3x + 6a - 4ax$

Now, let's solve them step by step:

Equation 1: $2x + 3y = 5ab - 10a^2$

This equation involves both $x$ and $y$, so it can't be solved for a single variable unless we have more information.

Equation 2: $5ab - 10a^2 = 6a^2x^3 - 4a^3x^2 + 2a^2x^2$

This is a cubic equation in terms of $x$ and $a$, but it can't be solved unless you specify values for $a$ and $b$.

Equation 3: $5x(x - 6) = 0$

This is actually two equations in one. The solutions are $x = 0$ and $x = 6$.

Equation 4: $2x^2 + 18x = 0$

This is a quadratic equation. Factoring $2x$ out, we get $2x(x + 9) = 0$, which gives solutions $x = 0$ and $x = -9$.

Equation 5: $9(x + 4) + x + 4 = 2x^2 - 3x + 6a - 4ax$

This is a linear equation involving $x$ and $a$. We can solve it for $x$ or $a$ once you specify values for the variables.

If you have specific values for $a$, $b$, or any other variable, please provide them, and I can help you find the solutions.