Question

(C+2)(c-3) (2а-1)(3а+4) (5х-у)(4x-y) 2 (a-2)(a-3a+6)

Answer 1

Ответ:

Объяснение:

1) (c+2)(c-3)=c²-3c+2c-6=c²-c-6

2) (2a-1)(3a+4)=6a²+8a-3a-4=6a²+5a-4

3) (5x-y)(4x-y)=20x²-5xy-4xy+y²=20x²-9xy+y²

4) (a-2)(a-3a+6)=a²-3a²+6a-2a+6a-12= -2a²+10a-12

Answer 2

To expand the given expression, you can use the distributive property, also known as the FOIL method (First, Outer, Inner, Last). Here's how you can expand the expression step by step:

1. Start with the first two factors, (C + 2)(C - 3):

   (C + 2)(C - 3) = C * C + C * (-3) + 2 * C + 2 * (-3) = C^2 - 3C + 2C - 6 = C^2 - C - 6

2. Next, expand the second two factors, (2a - 1)(3a + 4):

   (2a - 1)(3a + 4) = (2a)(3a) + (2a)(4) + (-1)(3a) + (-1)(4) = 6a^2 + 8a - 3a - 4 = 6a^2 + 5a - 4

3. Now, expand the third pair, (5x - y)(4x - y):

   (5x - y)(4x - y) = (5x)(4x) + (5x)(-y) + (-y)(4x) + (-y)(-y) = 20x^2 - 5xy - 4xy + y^2 = 20x^2 - 9xy + y^2

4. Finally, expand the last pair, (a - 2)(a - 3a + 6):

   (a - 2)(a - 3a + 6) = (a)(a) + (a)(-3a) + (a)(6) + (-2)(a) + (-2)(-3a) + (-2)(6) = a^2 - 3a^2 + 6a - 2a + 6a - 12 = a^2 - 3a^2 + 10a - 12

Now, you have all the expanded expressions:

1. (C + 2)(C - 3) = C^2 - C - 6
2. (2a - 1)(3a + 4) = 6a^2 + 5a - 4
3. (5x - y)(4x - y) = 20x^2 - 9xy + y^2
4. (a - 2)(a - 3a + 6) = a^2 - 3a^2 + 10a - 12

To find the product of all these expressions, simply multiply them together:

(C^2 - C - 6)(6a^2 + 5a - 4)(20x^2 - 9xy + y^2)(a^2 - 3a^2 + 10a - 12)

You can multiply these polynomials together, but the resulting expression will be quite lengthy. If you need the fully expanded form, you can perform the multiplication step by step or use a computer algebra system for assistance.