Question

Sin a + sinßякщо a-ß = 180​

Answer 1

Объяснение:

$\alpha -\beta =180^0\\sin\alpha +sin\beta =2*sin\frac{\alpha +\beta }{2} *cos\frac{\alpha -\beta }{2}=2*sin\frac{\alpha +\beta }{2}*cos\frac{180^0}{2}=\\=2*sin\frac{\alpha +\beta }{2}*cos90^0=2*sin\frac{\alpha +\beta }{2}*0=0.$

Answer 2

The equation you've written, "sin(a) + sin(ß) = 180," does not seem to be accurate. In trigonometric equations, the values of sine functions are bounded between -1 and 1, so the sum of two sine functions cannot be equal to 180.

If you meant to write a different equation or have a specific trigonometric problem in mind, please provide more context or clarify the equation, and I'll be happy to help you solve it.