Question

(6x−10)2−2(6x−10)+1=0​

Answer 1

Ответ:

поскольку сумма двух противоположных величин равна нулю, убираем их из выражения. Тогда:

1=0

х∈∅

Объяснение:

,,,,,

Answer 2

Ответ:

(6х-10)2-2(6х-10)+1=0

2(6х-10)-2(6х-10)+1=0

12х-20-12х+20+1=0

12х-12х-20+20+1=0

0+1=0

1≠0

Ответ: уравнение не имеет решений

Answer 3

To solve the quadratic equation (6x - 10)^2 - 2(6x - 10) + 1 = 0, we can use the substitution method to simplify the equation. Let y = 6x - 10. Then the equation becomes:

y^2 - 2y + 1 = 0

Now, we have a simpler quadratic equation. This equation can be factored as a perfect square:

(y - 1)^2 = 0

To solve for y, take the square root of both sides:

y - 1 = 0

Now, add 1 to both sides:

y = 1

Now that we have found the value of y, we can substitute it back into the original equation to find the values of x:

6x - 10 = 1

Add 10 to both sides:

6x = 11

Now, divide by 6:

x = 11/6

So, the solution to the equation (6x - 10)^2 - 2(6x - 10) + 1 = 0 is:

x = 11/6