Question

Log tg4 + log ctg4=​

Answer 1

Ответ:

$log(tg4)+log(ctg4)=log(\underbrace {tg4\cdot ctg4}_{1})=log\, 1=0$

Answer 2

Ответ:0

Объяснение:

Log(tg4*ctg4)=log1=0

Answer 3

To solve the expression:

log(tan^4(x)) + log(cot^4(x))

You can use logarithm properties to simplify it. The sum of logarithms with the same base is equivalent to the logarithm of the product of the arguments. In this case, you have a sum of logarithms with base 10, so you can rewrite it as a single logarithm:

log(tan^4(x) * cot^4(x))

Now, you can use trigonometric identities to simplify further. The tangent and cotangent are reciprocal trigonometric functions. Cotangent is the reciprocal of tangent, so cot(x) = 1/tan(x).

Now, we can rewrite the expression using this identity:

log((tan^4(x)) * (1/tan^4(x)))

Notice that (tan^4(x)) * (1/tan^4(x)) = 1, because the multiplication of a quantity and its reciprocal is always 1. Therefore, the expression simplifies to:

log(1)

The logarithm of 1 to any base is always 0. So, the final answer is:

0