Question

(x-4)⁴-15(x+4)²-16=03/x+1 - 2/x+3(дробь)​

Answer 1

Ответ:

100+1+1+1+1+1+1+1+1+1+1+1+=?

Answer 2

To solve the equation $(x-4)^4 - 15(x+4)^2 - 16 = \frac{3}{x+1} - \frac{2}{x+3}$, you can follow these steps:

Step 1: Simplify the equation by finding a common denominator for the fractions on the right-hand side.

$(x-4)^4 - 15(x+4)^2 - 16 = \frac{3(x+3) - 2(x+1)}{(x+1)(x+3)}$

Step 2: Expand the expressions in the equation and simplify.

$(x-4)^4 - 15(x+4)^2 - 16 = \frac{3x + 9 - 2x - 2}{(x+1)(x+3)}$

Simplify the right-hand side:

$(x-4)^4 - 15(x+4)^2 - 16 = \frac{x + 7}{(x+1)(x+3)}$

Step 3: Cross-multiply to get rid of the fraction:

$(x-4)^4 - 15(x+4)^2 - 16 = x + 7$

Step 4: Move all the terms to one side of the equation to set it equal to zero:

$(x-4)^4 - 15(x+4)^2 - 16 - x - 7 = 0$

Step 5: Simplify and rewrite the equation in standard form:

$(x-4)^4 - 15(x+4)^2 - x - 23 = 0$

This is the final equation in standard form. To solve it, you may need to use numerical methods or a computer algebra system, as it's a quartic equation (a polynomial of degree 4) and may not have simple algebraic solutions.