Question

У²−8у+16у²−16 ÷10у−40у²+4у,при у=60

Answer 1

Ответ:

=-1/5y(115y+28) либо можно написать -0.2y(115y+28)

Объяснение:

= -23y^2-4y-16/10y=-y(23y+4y-16/10)=-y(23y+28/5)=-1/5y(115y+28) либо можно написать -0.2y(115y+28)

=-83136

Answer 2

I see you've got an algebraic expression there. Let's simplify it step by step.

The expression is (u^2 - 8u + 16u^2 - 16) / (10u - 40u^2 + 4u) when u = 60.

First, let's combine like terms in the numerator: (1u^2 - 8u + 16u^2 - 16) / (10u - 40u^2 + 4u)

Combine the u^2 terms: (17u^2 - 8u - 16) / (10u - 40u^2 + 4u)

Now, let's factor the numerator: ((17u + 4)(u - 4)) / (10u - 4u - 4u + 4u)

Combine like terms in the denominator: ((17u + 4)(u - 4)) / (10u - 8u)

Now simplify further: ((17u + 4)(u - 4)) / (2u)

Now substitute u = 60: ((17 * 60 + 4)(60 - 4)) / (2 * 60)

Calculate the numerator and denominator separately: (1024 * 56) / 120

And the final result is: 47872 / 120

Simplify the fraction: 399.7333

So, when u = 60, the simplified expression is approximately 399.7333.