Question

125-2×5×(-1/9)+6×5-7×5×(-1/9)-150-6×5​

Answer 1

$125-2\times \:5\times \left(-1/9\right)+6\times \:5-7\times \:5\times \left(-1/9\right)-150-6\times \:5$

$=125-2\times \:5\times \frac{-1}{9}+6\times \:5-7\times \:5\times \left(-1/9\right)-150-6\times \:5$

$=125-2\times \:5\times \frac{-1}{9}+6\times \:5-7\times \:5\times \frac{-1}{9}-150-6\times \:5$

$=125-\left(-\frac{10}{9}\right)+6\times \:5-7\times \:5\times \frac{-1}{9}-150-6\times \:5$

$=125-\left(-\frac{10}{9}\right)+30-7\times \:5\times \frac{-1}{9}-150-6\times \:5$$=125-\left(-\frac{10}{9}\right)+30-\left(-\frac{35}{9}\right)-150-6\times \:5$

$=125-\left(-\frac{10}{9}\right)+30-\left(-\frac{35}{9}\right)-150-30$

$=125+\frac{10}{9}+30-\left(-\frac{35}{9}\right)-150-30$

$=\frac{1135}{9}+30-\left(-\frac{35}{9}\right)-150-30$

$=\frac{1405}{9}-\left(-\frac{35}{9}\right)-150-30$

$=160-150-30$

$=10-30$

$=-20$

Answer 2

To solve this expression, follow the order of operations (PEMDAS/BODMAS - Parentheses/Brackets, Exponents/Orders, Multiplication and Division, Addition and Subtraction) and perform the calculations step by step:

1. First, handle the multiplication and division from left to right: 125 - 2 × 5 × (-1/9) + 6 × 5 - 7 × 5 × (-1/9) - 150 - 6 × 5 125 - 10 × (-1/9) + 30 - 35 × (-1/9) - 150 - 30

2. Next, calculate the products and quotients: 125 - (-10/9) + 30 + (35/9) - 150 - 30

3. Now, add and subtract from left to right: 125 + 10/9 + 30 + 35/9 - 150 - 30

4. Combine the fractions: 125 + 10/9 + 30 + 35/9 - 150 - 30

5. Find a common denominator for the fractions, which is 9: (1125/9) + (10/9) + (270/9) + (35/9) - (1350/9) - (270/9)

6. Add and subtract the fractions: (1125 + 10 + 270 + 35 - 1350 - 270) / 9

7. Perform the arithmetic within the parentheses: (1130 + 305 - 1620) / 9

8. Continue with the addition and subtraction: (415 - 1620) / 9

9. Subtract: -1205 / 9

Now, you have the simplified result: -1205/9