
Cos(60°+2)×cos(60°-2)


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cos(4) - 1
2 4



To calculate the value of cos(60° + 2) × cos(60° - 2), you can use the trigonometric identities.
First, convert degrees to radians because trigonometric functions typically work with radians:
60 degrees = π/3 radians 2 degrees = 2π/180 radians = π/90 radians
Now, you can calculate the values:
cos(60° + 2) = cos(π/3 + π/90) cos(60° - 2) = cos(π/3 - π/90)
Use the sum and difference identities for cosine:
cos(A + B) = cos(A)cos(B) - sin(A)sin(B) cos(A - B) = cos(A)cos(B) + sin(A)sin(B)
In this case, A = π/3 and B = π/90:
cos(60° + 2) = cos(π/3)cos(π/90) - sin(π/3)sin(π/90) cos(60° - 2) = cos(π/3)cos(π/90) + sin(π/3)sin(π/90)
Now, use the values of cos(π/3) and sin(π/3), which are known:
cos(π/3) = 1/2 sin(π/3) = √3/2
And use the values of cos(π/90) and sin(π/90), which can be calculated as follows:
cos(π/90) = cos(π/3 - π/90) = cos(π/3)cos(π/90) + sin(π/3)sin(π/90) sin(π/90) = sin(π/3 - π/90) = sin(π/3)cos(π/90) - cos(π/3)sin(π/90)
Now, calculate cos(π/90) and sin(π/90):
cos(π/90) = (1/2)cos(π/90) + (√3/2)sin(π/90) sin(π/90) = (√3/2)cos(π/90) - (1/2)sin(π/90)
Let's denote cos(π/90) as "x" and sin(π/90) as "y." Then, we have the following system of equations:
x = (1/2)x + (√3/2)y y = (√3/2)x - (1/2)y
Solve this system of equations for x and y. First, isolate y in the second equation:
y = (√3/2)x - (1/2)y (3/2)y = (√3/2)x y = (√3/3)x
Now, substitute this expression for y into the first equation:
x = (1/2)x + (√3/2)y x = (1/2)x + (√3/2)(√3/3)x x = (1/2)x + (√3/6)x
Now, isolate x:
(2/2 - 1/2)x = (√3/6)x (1/2)x = (√3/6)x
Divide both sides by (1/2):
x = (√3/6)x
Now, you can solve for x:
(1 - √3/6)x = 0
x = 0
Now that you have the value of x, you can find the value of y using the second equation:
y = (√3/3)x y = (√3/3)(0) y = 0
So, cos(π/90) = x = 0 and sin(π/90) = y = 0.
Now, you can calculate the values of cos(60° + 2) and cos(60° - 2):
cos(60° + 2) = (1/2)(0) - (√3/2)(0) = 0 cos(60° - 2) = (1/2)(0) + (√3/2)(0) = 0
Therefore, cos(60° + 2) × cos(60° - 2) = 0.


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