Question

X-3 < 2x-3,4x +5 > 10- x;​

Answer 1

x-3 < 2x-3= x< 2x= x-2x < 0 = -x < 0 = x> 0

= x-2x < 0 = -x < 0 = x> 04x+5 > 10-x = 4x+x > 10-5 = 5x > 5 = x > 1

Answer 2

Ответ:

х-2х<-3+3

4х+х>10-5

-х<0

5х>5

х>0

х>1

ответ от 1 до бесконечности

Answer 3

To solve these inequalities, let's take them one at a time.

1. $X-3 < 2x-3$

To solve this, we'll isolate the variable x:

$X - 3 < 2x - 3$ $X - 2x < -3 + 3$ $-x < 0$

Since there is a negative sign in front of x, we need to flip the inequality sign:

$x > 0$

2. $4x + 5 > 10 - x$

To solve this, isolate the variable x:

$4x + 5 > 10 - x$ $4x + x > 10 - 5$ $5x > 5$

Divide by 5 to solve for x:

$x > 1$

So the solutions for the inequalities are $x > 0$ and $x > 1$. However, we need to find the intersection of these two sets, which means the final solution is $x > 1$.