Question

1)(x-2)(x-6)(x+1)(x+5)=-180 2)4(x+5)(x+6)(x+10)(x+12)=3x²

Answer 1

ОТВЕТ

х1=-4,х2=-3,х3=4,х4=5

Объяснение:

Answer 2

To solve these equations, we'll first simplify them and then find the values of $x$ that satisfy the equations.

Equation 1:

$(x - 2)(x - 6)(x + 1)(x + 5) = -180$

First, expand the left side:

$x^4 - 2x^3 - 6x^3 + 12x^2 + x^2 - 2x^2 - 10x + 20x - 180 = 0$

Simplifying further:

$x^4 - 7x^3 + 11x^2 - 10x - 180 = 0$

This equation is a quartic equation. Solving quartic equations can be complex and may not always have simple solutions. You might need to use numerical methods or a graphing calculator to find the approximate solutions.

Equation 2:

$4(x + 5)(x + 6)(x + 10)(x + 12) = 3x^2$

First, expand the left side:

$4x^4 + 124x^2 + 720x + 3600 = 3x^2$

Move all terms to one side to set the equation to zero:

$4x^4 + 121x^2 + 720x + 3600 = 0$

This is another quartic equation. As with the first equation, finding exact solutions might be challenging, and numerical methods or graphing techniques may be required to find approximate solutions.

Please note that solving quartic equations analytically can be quite involved and may not always lead to simple solutions. Numerical methods, such as the Newton-Raphson method or using graphing software, are often employed to find approximate solutions for such equations.