Question

[2x-4]^2-[x-1][x+1]

Answer 1

Ответ: 3х²-16х+17

Объяснение:

все просто

Answer 2

Ответ:

Объяснение:

[2x-4]²-[x-1][x+1]=(2x-4)²-(x²-1)=4x²-16x+16-x²+1=

=3x²-16x+17

Answer 3

To simplify the expression $(2x - 4)^2 - (x - 1)(x + 1)$, you can follow these steps:

1. Expand the square in $(2x - 4)^2$: $(2x - 4)^2 = (2x - 4)(2x - 4) = 4x^2 - 8x - 8x + 16$ Simplify further: $4x^2 - 16x + 16$

2. Expand the product $(x - 1)(x + 1)$ using the FOIL (First, Outer, Inner, Last) method: $(x - 1)(x + 1) = x^2 + x - x - 1$ Simplify further: $x^2 - 1$

Now, you can subtract the second expression from the first:

$(4x^2 - 16x + 16) - (x^2 - 1)$

Now, distribute the negative sign across the second expression:

$4x^2 - 16x + 16 - x^2 + 1$

Combine like terms:

$3x^2 - 16x + 17$

So, the simplified expression is $3x^2 - 16x + 17$.