Question

X4 - 8x2 + 7 = 0; (x2 - 5x + 4)(x2 – 5x + 1) = 28;3x - 5 3x+2 6x-5- 5x2 -1 x² + x x² - x x​

Answer 1

Ответ:

первое

и

второе

последнее фото это ответ ко второму

Answer 2

It looks like you've provided several mathematical expressions and equations. Let me address each one separately:

1. Solving the quadratic equation: You have the equation X^4 - 8X^2 + 7 = 0. You can solve it by factoring:

   X^4 - 8X^2 + 7 = (X^2 - 7)(X^2 - 1) = 0

   Now, you have two quadratic equations:

   a. X^2 - 7 = 0: X^2 = 7 X = ±√7

   b. X^2 - 1 = 0: X^2 = 1 X = ±1

   So, the solutions to the original equation are X = ±√7 and X = ±1.

2. Factoring the quadratic equation: You want to factor the equation (x^2 - 5x + 4)(x^2 - 5x + 1) = 28. To factor it, first move 28 to the left side:

   (x^2 - 5x + 4)(x^2 - 5x + 1) - 28 = 0

   Now, notice that both terms in the left side have a common factor of (x^2 - 5x + 1):

   (x^2 - 5x + 1)((x^2 - 5x + 4) - 28) = 0

   Simplify further:

   (x^2 - 5x + 1)(x^2 - 5x - 24) = 0

   Now, you have two quadratic equations:

   a. x^2 - 5x + 1 = 0: You can use the quadratic formula to find the roots. b. x^2 - 5x - 24 = 0: Factor this quadratic equation by finding two numbers that multiply to -24 and add up to -5. The numbers are -8 and 3.

3. Simplifying expressions: You've given a list of expressions, and it's not clear what you want to do with them. If you want to simplify them, here are the results:

   • 3x - 5
   • 3x + 2
   • 6x - 5
   • 5x^2 - 1
   • x^2 + x
   • x^2 - x

   If you have specific operations or questions related to these expressions, please provide more details, and I'd be happy to assist further.