Question

1)15х-30=15; 2)2х-5=х+11; 3)10х+80-5х=32-2х

Answer 1

Ответ:

1) 15х-30=15

15х=15+30

15х=45

х=3

2)2х-5=х+11

2х-х=11+5

х=16

3) 10х+80-5х=32-2х

80-32=-2х-10х+5х

48=-7х

х=-6 6/7

Answer 2

Ответ:

15x-30=15

X=3

2x-5=x+11

X=16

10x+80-5x=32-2x

6 6/7

Answer 3

Let's solve each of these equations one by one:

1. 15x - 30 = 15

First, add 30 to both sides of the equation to isolate the variable x:

15x - 30 + 30 = 15 + 30 15x = 45

Now, divide both sides by 15 to solve for x:

15x/15 = 45/15 x = 3

So, the solution to the first equation is x = 3.

2. 2x - 5 = x + 11

To solve this equation, start by subtracting x from both sides to isolate the variable x:

2x - x - 5 = x - x + 11 x - 5 = 11

Now, add 5 to both sides of the equation:

x - 5 + 5 = 11 + 5 x = 16

The solution to the second equation is x = 16.

3. 10x + 80 - 5x = 32 - 2x

First, simplify the equation by combining like terms on both sides:

(10x - 5x) + 80 = 32 - 2x

Now, simplify further:

5x + 80 = 32 - 2x

Next, subtract 80 from both sides:

5x + 80 - 80 = 32 - 2x - 80 5x = -2x - 48

Now, add 2x to both sides to isolate the variable x:

5x + 2x = -2x - 48 + 2x 7x = -48

Finally, divide both sides by 7 to find the value of x:

7x/7 = -48/7 x = -48/7

So, the solution to the third equation is x = -48/7.