Question

3(х+2)-4(х+1)=3-3х-3​

Answer 1

Ответ:

-1

Объяснение:

$3(x+2)-4(x+1)=3-3x-3$

$3x+6-4x-4=-3x$

$3x-4x+3x=-6+4$

$2x=-2$

$x=-1$

Answer 2

Let's solve the equation step by step:

$3(x + 2) - 4(x + 1) = 3 - \frac{3}{x} - \frac{3}{3}$

Distribute the numbers outside the parentheses:

$3x + 6 - 4x - 4 = -\frac{3}{x} - 1$

Combine like terms on both sides:

$-x + 2 = -\frac{3}{x} - 1$

Now, let's isolate $x$. First, get rid of the fraction by multiplying both sides by $x$:

$x(-x + 2) = -3 - x$

Distribute $x$:

$-x^2 + 2x = -3 - x$

Move all terms to one side of the equation to set it to zero:

$0 = -x^2 + 3x + 3$

Now, let's solve this quadratic equation. You can use the quadratic formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In this case, $a = -1$, $b = 3$, and $c = 3$. Plug these values into the formula:

$x = \frac{-3 \pm \sqrt{3^2 - 4(-1)(3)}}{2(-1)}$

Simplify the expression under the square root:

$x = \frac{-3 \pm \sqrt{9 + 12}}{-2}$

$x = \frac{-3 \pm \sqrt{21}}{-2}$

So, the solutions for $x$ are:

$x = \frac{-3 + \sqrt{21}}{-2} \quad \text{and} \quad x = \frac{-3 - \sqrt{21}}{-2}$