Question

Укажи линейную функцию график которой проходит через точку (10;-1) и пересекает ось Оу в точке с координатами (0;-7) ​

Answer 1

Ответ:

у=0,6х

Объяснение:

Answer 2

Linear Function Passing Through (10, -1) and Intersecting the y-axis at (0, -7)

To find a linear function that passes through the point (10, -1) and intersects the y-axis at (0, -7), we can use the point-slope form of a linear equation:

y - y1 = m(x - x1)

where (x1, y1) is the given point and m is the slope of the line.

Let's calculate the slope first using the given points:

m = (y2 - y1) / (x2 - x1)

Substituting the coordinates of the given points:

m = (-7 - (-1)) / (0 - 10) = -6 / -10 = 3/5

Now that we have the slope, we can substitute it into the point-slope form using the point (10, -1):

y - (-1) = (3/5)(x - 10)

Simplifying the equation:

y + 1 = (3/5)(x - 10)

To find the equation of the line, we can expand and rearrange the equation:

y + 1 = (3/5)x - 6

y = (3/5)x - 7

Therefore, the linear function that passes through the point (10, -1) and intersects the y-axis at (0, -7) is:

y = (3/5)x - 7