Question

Решите примеры 1) (a-b)n 2) (-5x+4y)2z 3) -6x (5y-2x) 4) (x^2-x+1)x ДАЮ 50 БАЛЛОВ

Answer 1

1)(a-b)n=an-bn

2)(-5x+4y)2z= -10xz+8yz

3)-6x(5y-2x)

-6x•5y-6x•(-2x)

-30xy+12x²

4)(x²-x+1)x

x²•x-x•x+x

x³-x²+x

Answer 2

1) (a-b)n To solve this expression, we need to know the values of a, b, and n. Let's assume a = 3, b = 2, and n = 4.

(a-b)n = (3-2)4 = 1 * 4 = 4

So, when a = 3, b = 2, and n = 4, the expression (a-b)n equals 4.

2) (-5x+4y)2z Again, we need to know the values of x, y, and z. Let's assume x = 2, y = 3, and z = 5.

(-5x+4y)2z = (-5*2 + 4*3) * 2*5 = (-10 + 12) * 10 = 2 * 10 = 20

So, when x = 2, y = 3, and z = 5, the expression (-5x+4y)2z equals 20.

3) -6x+(5y-2x)+4 We need to simplify this expression by combining like terms. Let's assume x = 1 and y = 2.

-6x+(5y-2x)+4 = -6*1 + (5*2 - 2*1) + 4 = -6 + (10 - 2) + 4 = -6 + 8 + 4 = 6

So, when x = 1 and y = 2, the expression -6x+(5y-2x)+4 equals 6.

4) (x^2-x+1)x We need to simplify this expression by multiplying. Let's assume x = 3.

(x^2-x+1)x = (3^2-3+1)*3 = (9-3+1)*3 = 7*3 = 21

So, when x = 3, the expression (x^2-x+1)x equals 21.

In conclusion, when the given values are substituted into the expressions, we get the following results: 1) (a-b)n = 4 2) (-5x+4y)2z = 20 3) -6x+(5y-2x)+4 = 6 4) (x^2-x+1)x = 21