Question

(2x-3)(5x+2)=x(10-3)-30решите пж и напишите полностью ​

Answer 1

Ответ:нет ответа

Объяснение:

10x^2+4x-15x-6=7x-30

10x^2-18x+24=0

D=324-960=-636<0

Нет ответа?

Answer 2

To solve the equation (2x-3)(5x+2) = x(10-3) - 30, we can start by simplifying both sides of the equation.

Simplifying the left side of the equation:

To simplify the left side of the equation, we can use the distributive property of multiplication over addition/subtraction. This property states that for any real numbers a, b, and c, a(b + c) = ab + ac.

Applying the distributive property to the left side of the equation, we get: (2x-3)(5x+2) = 2x * 5x + 2x * 2 - 3 * 5x - 3 * 2 = 10x^2 + 4x - 15x - 6 = 10x^2 - 11x - 6

Simplifying the right side of the equation:

To simplify the right side of the equation, we can first simplify the expression x(10-3) and then subtract 30.

Simplifying x(10-3), we get: x(10-3) = x * 10 - x * 3 = 10x - 3x = 7x

Now, subtracting 30 from 7x, we have: 7x - 30

Setting up the equation:

Now that we have simplified both sides of the equation, we can set them equal to each other: 10x^2 - 11x - 6 = 7x - 30

Solving the equation:

To solve this quadratic equation, we can rearrange it into standard form (ax^2 + bx + c = 0) and then use factoring, completing the square, or the quadratic formula.

Rearranging the equation, we get: 10x^2 - 11x - 6 - 7x + 30 = 0 10x^2 - 18x + 24 = 0

Now, we can try to factor the quadratic expression. However, after checking the discriminant (b^2 - 4ac), we can see that it is negative. This means that the quadratic equation does not have real solutions.

Therefore, the equation (2x-3)(5x+2) = x(10-3) - 30 does not have any real solutions.

Please let me know if you need any further clarification or assistance!