Question

Заданы три числа, идущие подряд. Известно, что разница между квадратом меньшего числа и произведением двух других равна 35. Найди заданные числа. Первое число: Второе число: Третье число: Помогите срочно

Answer 1

Пусть х- первое число, тогда
(х+1)- второе число
(х+2)- третье число , тогда
(дальше во вложении)
ответ: первое число -11, второе число-12, третье число-13

Answer 2

Problem Analysis

We are given three consecutive numbers, and it is known that the difference between the square of the smaller number and the product of the other two numbers is equal to 35. We need to find the three given numbers.

Solution

Let's assume the three consecutive numbers are x, x+1, and x+2.

According to the problem statement, the difference between the square of the smaller number (x^2) and the product of the other two numbers ((x+1)*(x+2)) is equal to 35.

Mathematically, we can represent this as:

x^2 - (x+1)(x+2) = 35

Expanding the equation:

x^2 - (x^2 + 3x + 2) = 35

Simplifying the equation:

x^2 - x^2 - 3x - 2 = 35

-3x - 2 = 35

-3x = 35 + 2

-3x = 37

Dividing both sides by -3:

x = -37/3

Since we are dealing with consecutive numbers, we can conclude that the given numbers are not integers. Therefore, there are no three consecutive numbers that satisfy the given conditions.

Answer

There are no three consecutive numbers that satisfy the given conditions.