Question

(Х^2-1)(х^2+4х+3)=0 Решите пожалуйста Срочнооо срочно

Answer 1

Ответ:

- 3;  - 1; 1

Объяснение:

см фото

Answer 2

Ответ:

Ну вот, там получается график как я понял

Объяснение:

Answer 3

Solving the Quadratic Equation

To solve the quadratic equation (x^2 - 1)(x^2 + 4x + 3) = 0, we can use the factored form of the equation to find the values of x that satisfy the equation.

First, let's factorize the quadratic equation: (x^2 - 1)(x^2 + 4x + 3) = 0

We can factorize x^2 - 1 as (x + 1)(x - 1) and x^2 + 4x + 3 as (x + 3)(x + 1).

So the equation becomes: (x + 1)(x - 1)(x + 3)(x + 1) = 0

Now, we can find the values of x by setting each factor equal to zero and solving for x.

1. Setting (x + 1) = 0: - x + 1 = 0 - x = -1

2. Setting (x - 1) = 0: - x - 1 = 0 - x = 1

3. Setting (x + 3) = 0: - x + 3 = 0 - x = -3

So, the solutions to the equation (x^2 - 1)(x^2 + 4x + 3) = 0 are: x = -1, 1, -3

Therefore, the solutions to the given quadratic equation are x = -1, 1, -3.