Question

Решите уравнение 2у^2-3у+1=0ПОМОГИТЕ ПОЖАЛУЙСТА РЕШИТЬ ​

Answer 1

$\boxed{ \underline{ \overline{ \mathbb{ATTACHED \: \: \: \: \: FILE}}}}.$

Answer 2

2у² - 3у + 1 = 0

а=2; b=-3; c=1

D=b²-4ac=9-8=1

y=(-b±√D)/(2a)=(3±1)/4=1; 0,5

Answer 3

Solving the Equation 2у^2 - 3у + 1 = 0

To solve the equation 2у^2 - 3у + 1 = 0, we can use the quadratic formula. The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x can be found using the formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In our case, a = 2, b = -3, and c = 1. Plugging these values into the quadratic formula, we get:

у = (-(-3) ± √((-3)^2 - 4 * 2 * 1)) / (2 * 2)

Simplifying further:

у = (3 ± √(9 - 8)) / 4

у = (3 ± √1) / 4

у = (3 ± 1) / 4

This gives us two possible solutions for у:

у = (3 + 1) / 4 = 4 / 4 = 1

у = (3 - 1) / 4 = 2 / 4 = 0.5

Therefore, the solutions to the equation 2у^2 - 3у + 1 = 0 are у = 1 and у = 0.5.