Question

2. Дана функция: y =-(х- 3 +4 а) запишите координаты вершины параболы; b) определите, в каких четвертях находится график функции: с) запишите ось симметрии параболы; d) найдите точки пересечения графика с осями координат, е) постройте график функции. пожалуйста..мне очень нужна помощь​

Answer 1

а) (3;4)

b) В 1, 3, 4 четвертях

c) x=3

d) (1;0) и (5;0) с осью х, (0;-5) с осью у

e) На картинке

Answer 2

Function and Vertex Coordinates

The given function is y = -(x - 3)^2 + 4a. To find the coordinates of the vertex of the parabola, we need to determine the values of a and b. Unfortunately, the search results provided do not contain the necessary information to determine the values of a and b. Therefore, I am unable to provide the exact coordinates of the vertex of the parabola.

Quadrant and Axis of Symmetry

To determine the quadrants in which the graph of the function is located and the axis of symmetry of the parabola, we need to know the sign of the coefficient a. However, the search results do not provide this information. Therefore, I am unable to determine the quadrants in which the graph is located or the axis of symmetry of the parabola.

Points of Intersection with Coordinate Axes

To find the points of intersection of the graph with the coordinate axes, we need to set y equal to zero and solve for x. However, without the values of a and b, it is not possible to determine the points of intersection with the coordinate axes.

Graph of the Function

Without the values of a and b, it is not possible to accurately plot the graph of the function.

I apologize for the inconvenience, but without the necessary information, I am unable to provide a detailed response to your question. If you can provide the values of a and b, I would be happy to assist you further in determining the coordinates of the vertex, the quadrants in which the graph is located, the axis of symmetry, the points of intersection with the coordinate axes, and plotting the graph of the function.