Question

. Какая фигура является графиком уравнения (х-3)(2у+5)=0?

Answer 1

Ответ:

простая бесконечная прямая. пересекается в точке у=$-\frac{5}{2}$.

Answer 2

График уравнения (х-3)(2у+5)=0

Уравнение (х-3)(2у+5)=0 представляет собой произведение двух множителей, равных нулю. Чтобы найти график этого уравнения, нужно рассмотреть каждый множитель отдельно и найти точки, в которых они обращаются в ноль.

Множитель (х-3) обращается в ноль, когда х=3. Это означает, что график этого множителя является вертикальной прямой, проходящей через точку (3, y), где y - любое число.

Множитель (2у+5) обращается в ноль, когда 2у=-5, или у=-5/2. Это означает, что график этого множителя является горизонтальной прямой, проходящей через точку (x, -5/2), где x - любое число.

Таким образом, график уравнения (х-3)(2у+5)=0 представляет собой пересечение вертикальной прямой х=3 и горизонтальной прямой у=-5/2.

График уравнения (х-3)(2у+5)=0:

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