Question

1) x2 + 10x + 25 = 0; 2)49x^2-42+9=0 Срочно

Answer 1

Ответ:

Если это квадратное ур-ние, тогда

Х²-10Х+25=0

Ищем дискриминант

D=(-10)²-4*1*25=100-100=0

Дискриминант равен 0 значит уравнение имеет один корень

Объяснение:

.

Answer 2

1. To solve the equation x^2 + 10x + 25 = 0, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 1, b = 10, and c = 25. Substituting these values into the formula:

x = (-(10) ± √((10)^2 - 4(1)(25))) / (2(1)) x = (-10 ± √(100 - 100)) / 2 x = (-10 ± √0) / 2 x = (-10 ± 0) / 2 x = -10 / 2 x = -5

Therefore, the solution to the equation x^2 + 10x + 25 = 0 is x = -5.

2. To solve the equation 49x^2 - 42x + 9 = 0, we can factorize it:

49x^2 - 42x + 9 = (7x - 3)(7x - 3)

The equation can be rewritten as:

(7x - 3)^2 = 0

Taking the square root of both sides:

7x - 3 = 0

Adding 3 to both sides:

7x = 3

Dividing both sides by 7:

x = 3/7

Therefore, the solution to the equation 49x^2 - 42x + 9 = 0 is x = 3/7.