Question

две семьи отправились на детский утренник первая семья купила два детских билета и один взрослый и всего заплатила 490 рублей. Вторая семья купила 3 детских билета и 2 взрослых и всего заплатила 860 рублей. Сколько стоит 1 детский билет и 1 взрослый ПОМОГИТЕ ПЛИЗ НЕ ИГНОРЬТЕ МНЕ СРОЧНО НАДОО

Answer 1

Образуем систему

$2x + y = 490 \\ 3x + 2y = 860$

Решаем

$- y = 2x - 490 \\ y = 490 - 2x \\ \\ 3x + 2(490 - 2x) = 860 \\ x = 120 \\ y = 490 - 2 \times 120 \\ y = 250$

X - Цена одного детского билета

Y - Цена одного Взроского билета

Удачи!

Answer 2

Calculation of Ticket Prices

To calculate the price of one child ticket and one adult ticket, we can set up a system of equations based on the information provided.

Let's assume the cost of one child ticket is C rubles and the cost of one adult ticket is A rubles.

From the given information, we can form the following equations:

Equation 1: 2C + A = 490 (First family's purchase) Equation 2: 3C + 2A = 860 (Second family's purchase)

To solve this system of equations, we can use substitution or elimination method.

Solving the System of Equations

Let's use the elimination method to solve the system of equations.

Multiplying Equation 1 by 2, we get: 4C + 2A = 980

Now, we can subtract Equation 2 from this new equation: (4C + 2A) - (3C + 2A) = 980 - 860 C = 120

Substituting the value of C into Equation 1, we can find the value of A: 2(120) + A = 490 240 + A = 490 A = 250

Answer

Based on the calculations, the cost of one child ticket is 120 rubles and the cost of one adult ticket is 250 rubles.

Please note that these calculations are based on the information provided and the assumption that the ticket prices are consistent for both families.