Question

Розв'язати систему способом підстановки 7(2х+у)-5(3х+у)=6 і 3(х+2у)=2(х+3у)=-6 СРОЧНО ДАЮ 70 БАЛОВ

Answer 1

$></p> <p>Шукаємо у підстановкої х=-6</p> <p>6+2у=6  ⇒ у=0</p> <p>Відповідь:(6;0)</p> <p></p> </div> <div class=$ 0 0

Answer 2

I can help you solve the system of equations by substitution method. Here are the steps:

- First, we need to isolate one variable in one of the equations. Let's choose the second equation and solve for x. We have:

$$3(x+2y) = 2(x+3y) - 6$$

- Simplifying, we get:

$$x = 6y - 6$$

- Next, we need to substitute this value of x into the other equation. We have:

$$7(2(6y-6) + y) - 5(3(6y-6) + y) = 6$$

- Simplifying, we get:

$$-9y + 42 = 6$$

- Solving for y, we get:

$$y = 4$$

- Finally, we need to plug this value of y into the expression for x. We have:

$$x = 6(4) - 6$$

- Simplifying, we get:

$$x = 18$$

- Therefore, the solution of the system is (18, 4).Розв\'язати+систему+способом+підстановки+7(2х+у)-5(3х+у)=6+і+3(х+2у)=2(х+3у)=-6