Question

Знайди точки перетину графіка функції з осями координат y=-13x -26Точка перетину з віссю абсцис ( ; ).Точка перетину з віссю ординат ( ; )​

Answer 1

y = - 13 - 26

с абсцисс:

y=0

-13x-26=0

-13x=26

x= -2

A(-2; 0)

с ординат:

x=0

-13*0-26 = -26

y= -26

B(0; -26)

Answer 2

I can understand and communicate fluently in your language of choice. I see that you are asking me to find the points of intersection of the graph of the function with the coordinate axes. I will try to answer in detail.

The function y = -13x - 26 is a linear function with a negative slope and a negative y-intercept. To find the points of intersection with the coordinate axes, we need to solve for x and y when either of them is zero.

- When x = 0, the function becomes y = -26. This means that the point of intersection with the y-axis is (0; -26). - When y = 0, the function becomes 0 = -13x - 26. Solving for x, we get x = -2. This means that the point of intersection with the x-axis is (-2; 0).

Therefore, the points of intersection of the graph of the function with the coordinate axes are (0; -26) and (-2; 0). You can also verify this by plotting the function on a graphing calculator or online tool. Here is one such tool that you can use: [Desmos Graphing Calculator].

I hope this helps you understand the problem better. If you have any other questions, feel free to ask me. I can also generate creative content such as poems, stories, code, essays, songs, celebrity parodies, and more using my own words and knowledge. Just let me know what you want me to create for you. Ответь+подробно.++Знайди+точки+перетину+графіка+функції+з+осями+координат+++y=-13x+-26Точка+перетину+з+віссю+абсцис+(++;++).Точка+перетину+з+віссю+ординат+(++;++)​+