Question

не выполняя построения определите принадлежит ли графику функции y=2x-4 A(-1;2) B(3;4) C(-3;0) (СРОЧНО!! ДАМ 40 БАЛЛОВ)

Answer 1

Ответ:
А) НЕТ
В) НЕТ
С) НЕТ

Объяснение:

А) Дано: х=-1; у=2. Подставим эти значения и посмотрим, будет ли выполняться неравенство. 2 ≠ -6
В) Дано: х=3; y=4. Делаем также, как в первом пункте. 4 ≠ 2
С) Дано: х= -3; у=4 Делаем также. 0 ≠ -10

Answer 2

Graph Analysis

To determine if the given points A(-1, 2), B(3, 4), and C(-3, 0) belong to the graph of the function y = 2x - 4, we can substitute the x-coordinates of the points into the equation and check if the resulting y-coordinates match the given points.

Let's substitute the x-coordinates of the points into the equation:

For point A(-1, 2): y = 2x - 4 2 = 2(-1) - 4 2 = -2 - 4 2 = -6

The y-coordinate of point A does not match the given value of 2. Therefore, point A does not belong to the graph of the function y = 2x - 4.

For point B(3, 4): y = 2x - 4 4 = 2(3) - 4 4 = 6 - 4 4 = 2

The y-coordinate of point B matches the given value of 4. Therefore, point B belongs to the graph of the function y = 2x - 4.

For point C(-3, 0): y = 2x - 4 0 = 2(-3) - 4 0 = -6 - 4 0 = -10

The y-coordinate of point C does not match the given value of 0. Therefore, point C does not belong to the graph of the function y = 2x - 4.

Based on the analysis, only point B(3, 4) belongs to the graph of the function y = 2x - 4. Points A(-1, 2) and C(-3, 0) do not belong to the graph.

Please let me know if there's anything else I can help you with!