Question

0,3х(х-4)+1,2-2,7=0 помогите

Answer 1

Ответ:

Сначала раскроем скобки , затем приведём подобные члены и упростим выражение в левой части равенства .

$0,3x\, (x-4)+1,2-2,7=0\\\\0,3x^2-1,2x-1,5=0\ \Big|\cdot 10\\\\3x^2-12x-15=0\ \Big|:3\\\\x^2-4x-5=0\\\\x_1=-1\ ,\ x_2=5\ \ (teorema\ Vieta)\\\\Otvet:\ x_1=-1\ ,\ x_2=5\ .$

Answer 2

I can help you solve this equation. First, let's simplify it by removing the spaces and the plus signs:

$$0.3x(x-4)+1.2-2.7=0$$

Next, let's expand the brackets and collect the like terms:

$$0.3x^2-1.2x-1.5=0$$

Now, we can use the quadratic formula to find the values of $x$ that satisfy the equation:

$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$

In this case, $a=0.3$, $b=-1.2$, and $c=-1.5$. Plugging these values into the formula, we get:

$$x=\frac{1.2\pm\sqrt{1.2^2-4(0.3)(-1.5)}}{2(0.3)}$$

Simplifying further, we get:

$$x=\frac{1.2\pm\sqrt{3.6}}{0.6}$$

$$x=\frac{1.2\pm1.8974}{0.6}$$

Finally, we can find the two possible solutions for $x$ by using the plus and minus signs:

$$x=\frac{1.2+1.8974}{0.6}\approx5.16$$

$$x=\frac{1.2-1.8974}{0.6}\approx-1.16$$

Therefore, the equation has two solutions: $x\approx5.16$ or $x\approx-1.16$. I hope this helps you understand how to solve quadratic equations.Ответь+подробно.++0,3х(х-4)+1,2-2,7=0+помогите+