Question

(x-2)(x-3)=6 хееееелп

Answer 1

Объяснение:

x^2-3x-2x+6=6

x^2-5x=0

x(x-5)=0

x=0;

x-5=0

x=5

Answer 2

To solve the equation (x-2)(x-3) = 6, we can start by expanding the left side of the equation using the distributive property. This gives us:

(x - 2)(x - 3) = 6 x^2 - 3x - 2x + 6 = 6 x^2 - 5x + 6 = 6

Next, we can simplify the equation further by subtracting 6 from both sides:

x^2 - 5x = 0

Now, let's factor the equation:

x(x - 5) = 0

This equation will be true if either x = 0 or x - 5 = 0. Solving these two equations separately, we have:

x = 0 or x - 5 = 0

For x = 0, the equation is satisfied.

For x - 5 = 0, adding 5 to both sides gives us:

x = 5

Therefore, the solutions to the equation (x-2)(x-3) = 6 are x = 0 and x = 5.