Question

A) (7-2x)²-(1-x)(x+1)

Answer 1

Ответ:

Ответ:

$5 {x}^{2} - 28x + 48$

Answer 2

Ответ:

5х²-28х+48

Объяснение:

49-28х+4х²-(1-х)*(1+х)

49-28х+4х²-(1-х²)

49-28х+4х²-(1+х²

48-28х+5х²

5х²-28х+48х

Answer 3

To simplify the expression (7-2x)² - (1-x)(x+1), we can expand the squared term and distribute the product. Let's go step by step:

(7 - 2x)² - (1 - x)(x + 1)

Expanding the squared term: (7 - 2x) * (7 - 2x) - (1 - x)(x + 1)

Using the FOIL method to multiply the squared term: (49 - 14x - 14x + 4x²) - (x - x² + 1 - x)

Simplifying the terms within the squared term: (49 - 28x + 4x²) - (x - x² + 1 - x)

Rearranging the terms: 49 - 28x + 4x² - x + x² - 1 + x

Combining like terms: 4x² + x² - 28x - x + x - 1 + 49

Combining like terms again: 5x² - 28x + 48

Therefore, the simplified expression is 5x² - 28x + 48.