Question

Виконайте множення многочленів в 1) (y+2) (Зу-5) 2) (x-y) (x²-x-2) 3) 3z(2z-1)+(z-3)(z+2)​

Answer 1

Написать в ручную не смог потому что в клаве степеней нет сори)

Answer 2

1. (y+2)(z-5): To multiply these polynomials, we can use the distributive property. Multiply each term in the first polynomial by each term in the second polynomial and then combine like terms, if any.

(y+2)(z-5) = y(z-5) + 2(z-5) = yz - 5y + 2z - 10

So, the product of (y+2)(z-5) is yz - 5y + 2z - 10.

2. (x-y)(x²-x-2): Similarly, we'll use the distributive property to multiply the terms.

(x-y)(x²-x-2) = x(x²-x-2) - y(x²-x-2) = x³ - x² - 2x - yx² + yx + 2y = x³ - x² - yx² - 2x + yx + 2y

Therefore, the product of (x-y)(x²-x-2) is x³ - x² - yx² - 2x + yx + 2y.

3. 3z(2z-1) + (z-3)(z+2): Again, apply the distributive property to multiply the terms.

3z(2z-1) + (z-3)(z+2) = 6z² - 3z + z(z+2) - 3(z+2) = 6z² - 3z + z² + 2z - 3z - 6 = 7z² - 4z - 6

Hence, the product of 3z(2z-1) + (z-3)(z+2) is 7z² - 4z - 6.