Question

(-x+5)²=(-z-2)²=(-n+4)²=(-m-10)²​=

Answer 1

1)x²-10x+25

2)z²+4z+4

3)n²-8n+16

4)m²+20+100

Answer 2

To find the values of x, z, n, and m that satisfy the given equation, we can solve each quadratic equation separately.

For the equation (-x + 5)² = (-z - 2)², we can expand both sides of the equation:

x² - 10x + 25 = z² + 4z + 4

Rearranging the terms, we get:

x² - 10x - z² - 4z + 21 = 0

This is a quadratic equation in terms of x and z. Similarly, for the equation (-n + 4)² = (-m - 10)², we can expand and rearrange the terms:

n² - 8n + 16 = m² + 20m + 100

n² - 8n - m² - 20m - 84 = 0

Again, this is a quadratic equation in terms of n and m.

To find the solutions, we need additional information or constraints for the variables x, z, n, and m. Without further information, we cannot determine unique values for these variables.