Question

X²-(2a-b)x+ a²-ab-2b² = 0;​

Answer 1

Ответ:

Объяснение:прости просто не могу обяснить

Answer 2

The given equation is a quadratic equation in the variable x. It can be written in the standard form as:

x² - (2a - b)x + a² - ab - 2b² = 0

To solve this quadratic equation, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

Comparing the given equation with the standard form, we can identify:

a = 1 b = 2a - b = -b + 2a c = a² - ab - 2b²

Now let's substitute these values into the quadratic formula:

x = (-(2a - b) ± √((2a - b)² - 4(1)(a² - ab - 2b²))) / (2(1))

Simplifying further:

x = (-(2a - b) ± √(4a² - 4ab + b² - 4a² + 4ab + 8b²)) / 2

x = (-(2a - b) ± √(9b² + 4b²)) / 2

x = (-(2a - b) ± √(13b²)) / 2

x = (-(2a - b) ± √(13) * √(b²)) / 2

x = (-(2a - b) ± √(13) * b) / 2

Therefore, the solutions to the quadratic equation x² - (2a - b)x + a² - ab - 2b² = 0 are:

x = (-(2a - b) + √(13) * b) / 2 x = (-(2a - b) - √(13) * b) / 2