Question

Log(5)(22)-log(5)(11)-log(5)(10)​

Answer 1

$log_{5}22 - log_{5}11-log_{5}10 = log_{5}\frac{22}{11} - log_{5}10 = log_{5}2-log_{5}10 = log_{5}\frac{2}{10} = log_{5}\frac{1}{5} = -1$Объяснение:

$log_{a}b - log_{a}c = log_{a}\frac{b}{c}\\log_{a}b + log_{a}c = log_{a}b*c\\log_{a}a = 1\\log_{a}\frac{1}{a} = -1$

Answer 2

Ответ: log 5 (22/11)-log 5 (10)=log 5(0,2)=-1. Всё просто.

Объяснение:

Answer 3

To simplify the expression, let's use the logarithmic properties:

1. The logarithm of a product is equal to the sum of the logarithms of the individual factors.
2. The logarithm of a quotient is equal to the difference of the logarithms of the numerator and denominator.

Using these properties, we can rewrite the expression as follows:

log(5)(22) - log(5)(11) - log(5)(10) = log(5)(22/11) - log(5)(10)

Simplifying further, we have:

log(5)(2) - log(5)(10)

Since log(5)(10) = log(5)(2 * 5) = log(5)(2) + log(5)(5) = log(5)(2) + 1 (using property 1 above), we can substitute this back into the expression:

log(5)(2) - (log(5)(2) + 1)

Now, combining like terms, we get:

log(5)(2) - log(5)(2) - 1

The two logarithms of 2 cancel each other out:

0 - 1

Finally, we have:

-1

Therefore, log(5)(22) - log(5)(11) - log(5)(10) simplifies to -1.