Question

(5-y)в квадрате -y (y-3) при y= -2/7​

Answer 1

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На фото

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Answer 2

To evaluate the expression (5-y)^2 - y(y-3) when y = -2/7, we substitute -2/7 for y:

(5 - (-2/7))^2 - (-2/7)((-2/7) - 3)

Simplifying further:

(5 + 2/7)^2 - (-2/7)(-2/7 - 3)

(5 + 2/7)^2 - (-2/7)(-23/7)

To calculate this expression, we need to perform the following steps:

1. Evaluate (5 + 2/7)^2: (5 + 2/7)^2 = (37/7)^2 = 1369/49

2. Evaluate (-2/7)(-23/7): (-2/7)(-23/7) = 46/49

Now substitute these values back into the original expression:

1369/49 - 46/49

Finally, subtract the fractions:

(1369 - 46)/49 = 1323/49

Therefore, when y = -2/7, the expression (5-y)^2 - y(y-3) equals 1323/49.