Question

(x^3-2x+4)-4X+8-(X^3-5X)=0

Answer 1

$(x^3-2x+4)-4x+8-(x^3-5x)=0 \\\\x^3-2x+4-4x+8-x^3+5x=0 \\\\12-x=0\\\\-x=-12\ \ \ |:(-1)\\\\x=12$

Answer 2

Let's simplify and solve the given equation:

Starting with the left side, we can combine like terms and simplify:

(x^3 - 2x + 4) - 4x + 8 - (x^3 - 5x) = 0 x^3 - 2x + 4 - 4x + 8 - x^3 + 5x = 0 3x + 12 = 0 3x = -12 x = -4

Therefore, the solution to the given equation is x = -4.