Question

X²-3x+2=0. x²-4x+3=0.

Answer 1

1. D = 3^2 - 4 * 2 = 1
x1 = 2; x2 = 1
2. D = 4^2 - 4*3 = 4
x1 = 1; x2 = 3

Answer 2

To solve these equations, we can use the quadratic formula, which states that for an equation of the form ax² + bx + c = 0, the solutions are given by:

x = (-b ± sqrt(b² - 4ac)) / 2a

Let's apply this formula to each of the equations:

For x² - 3x + 2 = 0, we have a = 1, b = -3, and c = 2. Substituting these values into the quadratic formula, we get:

x = (-(-3) ± sqrt((-3)² - 4(1)(2))) / 2(1) x = (3 ± sqrt(9 - 8)) / 2 x = (3 ± 1) / 2

So the solutions are x = 2 and x = 1.

For x² - 4x + 3 = 0, we have a = 1, b = -4, and c = 3. Substituting these values into the quadratic formula, we get:

x = (-(-4) ± sqrt((-4)² - 4(1)(3))) / 2(1) x = (4 ± sqrt(16 - 12)) / 2 x = (4 ± 2) / 2

So the solutions are x = 3 and x = 1.