Question

(x-5)(x-3)-(x+1)(x+2) при x=-2 10/11

Answer 1

(x-5)(x-3)-(x+1)(x+2)=$x^{2}$-5x-3x+15-($x^{2}$+2x+x+2)=$x^{2}$-8x+15-$x^{2}$-2x-x-2=-11x+13

Подставляем:

-11*(-2$\frac{10}{11}$)+13=-11*(-$\frac{32}{11}$)+13=32+13=45

Ответ: 45

Answer 2

To evaluate the expression (x-5)(x-3)-(x+1)(x+2) at x=-2 10/11, we need to substitute that value into the expression:

(-2 10/11 - 5)(-2 10/11 - 3) - (-2 10/11 + 1)(-2 10/11 + 2)

To simplify the expression, we can start by converting the mixed number -2 10/11 into an improper fraction:

-2 10/11 = -(2*11 + 10)/11 = -32/11

Now we can substitute this value into the expression and simplify:

((-32/11) - 5)((-32/11) - 3) - ((-32/11) + 1)((-32/11) + 2) = ((-157/11))((-95/11)) - ((-21/11))((-58/11)) = 1499/121 - 1218/121 = 281/121

Therefore, the value of the expression at x=-2 10/11 is 281/121.